Question

The acute angles of a right triangle are in the ratio 4:5. find each of these angles ​

Answer 1

Answer:

Let the first acute angle be 4x

Second acute angle be 5x

A.T.Q

4x+5x+90°=180°(Angle sum property)

9x=180°-90°

9x=90

x=90/9

x=10

First acute angle=10×4=40

Second acute angle=10×5= 50

Answer 2

Step-by-step explanation:

let the ratio of these two angles be 4x and 5x

then

4x+5x+ angel c =180

9x=180

x=180÷9

x=20

first angle is 20

second angle is 4x=4×20=80

third angle is 5x=5×20=100

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