The acute angles of the right triangle are in the ratio 2:7,find all the triangles.
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Answered by
17
Let the name of the triangle be ABC,
Let angle B be 90° [Since it is a right angle triangle]
Angle A : Angle C = 2 : 7 [Given]
(2+7 = 9 ; Angle A + Angle C = 90°)
Angle A = (2/9) * 90
= 2 * 10
= 20°
Angle C = (7/9)* 90
= 7*10
= 70°
[Or Angle C + Angle A = 90°
Angle C = 90°- Angle A
= 90°-20°
= 70°]
Therefore Angle A = 20° ; Angle B = 90° and Angle C = 79°
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Let angle B be 90° [Since it is a right angle triangle]
Angle A : Angle C = 2 : 7 [Given]
(2+7 = 9 ; Angle A + Angle C = 90°)
Angle A = (2/9) * 90
= 2 * 10
= 20°
Angle C = (7/9)* 90
= 7*10
= 70°
[Or Angle C + Angle A = 90°
Angle C = 90°- Angle A
= 90°-20°
= 70°]
Therefore Angle A = 20° ; Angle B = 90° and Angle C = 79°
HOPE THIS ANSWER HELPS YOU
PLEASE MARK THIS ANSWER AS THE BRAINLIEST
Answered by
17
Answer:
The angles of the triangle are 20°,70° and 90°.
Step-by-step explanation:
Let all the acute angles be 2x° and 7x°
All the angles of a triangle = 180°
One angle of a right triangle = 90°
So, all the angles of the triangle are --
=> 2x° + 7x° + 90° = 180°
=> 9x° + 90° = 180°
=> 9x° = 90°
So, x = 10
Since x = 10
Hence, 2x° = 20° and 7x° = 70°.
Hope this helps you buddy! Mark me brainliest please.
Anonymous:
Thank u
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