Question

the AD,BE and CF of a ∆ABC,intersect at G. if AG=6cm find AD.​

Answer 1

Answer:

GD

AG

=

1

2

GD

6

=

1

2

2×GD=6×1

2GD=6

GD=

2

6

=3cm

(ii)

GE

BG

=

1

2

⇒

BG+GE

BG

=

2+1

2

⇒

BE

BG

=

3

2

BG=

3

2

×BE=

3

2

×9 cm

=2×3cm=6cm

(iii)Again,

GF

CG

=

1

2

⇒

GF

CG+GF

=

1

2+1

⇒

GF

CF

=

1

3

⇒

4.5

CF

=

1

3

⇒CF=3×4.5=13.5 cm