Question

The addition of three successive multiple of 9 is 81. find out the multiples.​

Answer 1

Answer:

Let the numbers = 9x, 9x+9, 9x+ 18

So

9x + 9x+9+9x+ 18 = 81

27x = 54

x = 2

So the required multiples are 18, 27, 36

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Answer 2

Given : addition of three successive multiples of 9 is 81.

To Find :  the multiples​

Solution:

Let say three successive multiples of 9  

are 9k , 9(k+1) , 9(k+2)

Sum = 9k + 9(k + 1) + 9(k + 2)

= 9k + 9k + 9 + 9k + 18

= 27k + 27

= 27 ( k + 1)

The addition of three successive multiples of 9 is 81.

=>  27 ( k + 1) = 81

=> k + 1  = 3

=> k  = 2  

9k = 18

9(k+1) = 27

9(k+2) = 36

18 , 27 & 36 are three successive multiples of 9   whose addition is 81

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