Question

the addition of three successive multiples of 9 is 81.find out the multiples​

Answer 1

Answer:

18, 27, 36.

Step-by-step explanation:

let the no.s be 9x, 9(x+1), 9(x+2).

9x+9x+9+9x+18 = 81

27x+27 = 81

27x = 54

x = 2

So, the multiples are, 18, 27, 36.

Hope this helps you...........................

Answer 2

Given :

The addition of three successive multiples of 9 is 81.

To find:

The three multiples of 9.

Solution:

Let the consecutive multiples of 9 are 9x, 9(x+1), 9(x+2)

As it is given in the question that the sum of the multiples is 81 so,

• 9x+9(x+1)+9(x+2) = 81
• 9x+9x+9+9x+18 = 81
• 27x+27 = 81
• 27x = 81-27
• 27x = 54
• x = 54/27
• x = 2

so the multiple of 9 are given by:

• 9x = 9×2 = 18
• 9(x+1) = 9(2+1) = 9×3 = 27
• 9(x+2) = 9(2+2) = 9×4 = 36

The three consecutive multiples of 9 are 18, 27, and 36.