Question

the addition of three successive multiples of 9 is 81 find out the multiples​

Answer 1

Answer:

18, 27 and 36

Step-by-step explanation:

Let the no.s be 9x, 9(x+1), 9(x+2).9x+9x+9+9x+18 = 8127x+27 = 8127x = 54x = 2So, the multiples are, 18, 27 and 36

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Answer 2

$\huge\mathfrak\blue{Answer:}$

Multiple of a Number :

• A number that can be divided by the other given number without leaving any Remainder is know as Multiple of a given number
• For ex : 12 and 18 are multiples of 6

Given:

• We have been given that the sum of 3 consecutive multiples of 9 is 81

To Find:

• We have to find the 3 Multiples

Solution:

Let the three consecutive multiples be

9x , 9 ( x + 1 ) , 9 ( x + 2 )

$\underline{\large\mathfrak\red{According \: to \: the \: Question:}}$

$\implies \boxed{\sf{Sum \: of \: 3 \: consecutive \: multiples = 81} }$

$\implies \sf{ 9x + 9 \: ( x + 1 ) + 9 \: ( x + 2 ) = 81}$

$\implies \sf{ 9x + 9x + 9 + 9x + 18 = 81}$

$\implies \sf{27x + 27 = 81}$

$\implies \sf{27x = 54}$

$\implies \sf{x = \dfrac{54}{27}}$

$\implies \boxed{\sf{x = 2}}$

_______________________________

$\underline{\large\mathfrak\orange{Finding \: the \: Multiples }}$

$\mapsto \sf{9x = 9 \times 2 = 18}$

$\mapsto \sf{9 \: ( x + 1 ) = 9 \: (2+1) =9\times 3 = 27}$

$\mapsto \sf{9 \: (x +2) = 9 \: (2+2) = 9 \times 4 = 36}$

________________________________

$\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}$

$\large\boxed{\sf{Required \: Multiples = 18 , 27 , 36 }}$

________________________________

$\huge\mathtt\green{Verification:}$

☞ Given the Sum of three consecutive multiples of 9 is 81

$\mapsto \sf{Sum = 18 + 27 + 36 }$

$\mapsto \boxed{\sf{Sum = 81 }}$