Question

the addition of three successive multiples of 9 is 81 .find out the multiples ​

Answer 1

Answer:

1 8 , 27 , 36

Step-by-step explanation:

18 + 27 + 36 = 81

18 , 36 and 27 are successive multiples of 9

9 × 2 = 18

9× 3 = 27

9× 4 = 36

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Answer 2

Given : addition of three successive multiples of 9 is 81.

To Find :  the multiples​

Solution:

Let say three successive multiples of 9  

are 9k , 9(k+1) , 9(k+2)

Sum = 9k + 9(k + 1) + 9(k + 2)

= 9k + 9k + 9 + 9k + 18

= 27k + 27

= 27 ( k + 1)

The addition of three successive multiples of 9 is 81.

=>  27 ( k + 1) = 81

=> k + 1  = 3

=> k  = 2  

9k = 18

9(k+1) = 27

9(k+2) = 36

18 , 27 & 36 are three successive multiples of 9   whose addition is 81

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