the addition of three successive multipliesof 9 is 81 find out this multiplies
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AnswEr:-
Your Answers Are,
- 18
- 27 and
- 36.
ExplanaTion:-
Given:-
- The addition of three successive multiple of 9 is 81.
To Find:-
- These three multiples.
Now,
Let the three successive multiples of 9 be, 9x, 9(x+1) and 9(x+2).
So ATQ,
↦ 9x + 9(x+1) + 9(x+2) = 81.
↦ 9x + 9x + 9 + 9x + 18 = 81.
[By Opening Brackets].
↦ 27x + 27 = 81.
↦ 27 (x + 1) = 81.
[Taking 27 as common].
↦ x + 1 = 81/27.
↦ x + 1 = 3.
↦ x = 3 - 1.
↦ x = 2.
Therefore,
The Required Multiples are,
↦ 9x = 9 × 2 = 18.
↦ 9(x + 1) = 9(3) = 27.
↦ 9(x + 2) = 9(4) = 36.
So these multiples are 18, 27 and 36.
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