Question

the addition of three succsessive multiple of 9 is 81 find out the multiples​

Answer 1

Answer:

Step-by-step explanation:

Proper question :- The sum of three consecutive multiples of 9 is 81. Which is the least among these three multiples?

Solution :-

Let the three consecutive multiples of 9 be x, x + 9 and x + 18

Their sum is 81

According to the given condition,

x + x + 9 + x + 18 = 81

➾ 3x + 27 = 81

➾ 3x = 81 - 27

➾ 3x = 54

➾ x = 18

∴ Smaller number ➾ x

➾  

∴ Second number ➾ x + 9

➾ 18 + 9

➾  

∴ Third number ➾ x + 18

➾ 18 + 18

➾ 36

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Answer 2

Let the numbers be 9x ,9x + 9 and 9x + 18

{ Since they are multiples of 9 }

Thus

$9(x) + 9(x + 1) + 9(x + 2) = 81$

$9x + 9x + 9 + 9x + 18 = 81$

$27x + 27 = 81$

$27x = 81 - 27 = 54$

$x = \frac{54}{27}$

$x = 2$

Thus the numbers are

9x = 9(2) = 18

9x + 9 = 18 + 9 = 27

9x + 18 = 18 + 18 = 36

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