the additive inverse of a number divided by twelve is the same as one less then three times its reciprocal.find the number
Answers
Answered by
21
Let the number be x.
We know that,
Additive inverse of this number = -x
Reciprocal = 1/x .
According to the question,
-x/12 = 3/x - 1
-x/12 = 3 - x / x
-x² = 12 ( 3 - x)
-x² = 36 - 12x
x² - 12x + 36 = 0
x² - 6x - 6x + 36 = 0
x ( x - 6 ) -6 ( x - 6 ) = 0
( x - 6 ) = 0
x = 6 .
Therefore, The number is 6 .
We know that,
Additive inverse of this number = -x
Reciprocal = 1/x .
According to the question,
-x/12 = 3/x - 1
-x/12 = 3 - x / x
-x² = 12 ( 3 - x)
-x² = 36 - 12x
x² - 12x + 36 = 0
x² - 6x - 6x + 36 = 0
x ( x - 6 ) -6 ( x - 6 ) = 0
( x - 6 ) = 0
x = 6 .
Therefore, The number is 6 .
anuj982733:
thankyou
Answered by
7
Hello user☺☺
Let the number be x
So, the additive inverse will be -x
Now, A.T.Q. , we have
-x/12 = 3/x - 1
x/12 + 3/x = 1
x^2 + 36 = 12x
x^2 -12x + 36 = 0
(x-6)^2 = 0
(x-6) = 0
x = 6.
So, the number will be 6.
Hope this will help☺☺
Let the number be x
So, the additive inverse will be -x
Now, A.T.Q. , we have
-x/12 = 3/x - 1
x/12 + 3/x = 1
x^2 + 36 = 12x
x^2 -12x + 36 = 0
(x-6)^2 = 0
(x-6) = 0
x = 6.
So, the number will be 6.
Hope this will help☺☺
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