Computer Science, asked by dhrumzZ9971, 1 year ago

the address of a word in a byte addressable 1 mb physical memory is 0xab8f2. this word upon bringing to the cache is mapped to set 30. the word length of the processor is 16 bits. how many words can be accommodated in each cache block?

Answers

Answered by Anonymous
0
Answer: (C) 

Explanation:

In a k-way set associate mapping, cache memory is divided into sets, each of size k blocks.
Size of Cache memory = 16 KB
As it is 4-way set associative,K = 4
Block size B = 8 words
The word length is 32 bits.
size of Physical address space = 4 GB.

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