The adjacent angles of a parallelogram are (3x-12) and (52+2x). Find the angles of the parallelogram?
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Answered by
10
Hi sum of adjacent angles of a parallelogram is 180.
Therefore (3x-12)+(52+2x) = 180
i.e. 5x+40 = 180
or 5x = 140
thus x = 28
Therefore the angles are
(3×28-12) and (52+2×28)
i.e. 72 and 108
Therefore (3x-12)+(52+2x) = 180
i.e. 5x+40 = 180
or 5x = 140
thus x = 28
Therefore the angles are
(3×28-12) and (52+2×28)
i.e. 72 and 108
Answered by
6
Answer:
sum of adjacent angle of triangle=180degree.
(3x-12)+(52+2x)=180 degree
5x+40=180degree
5x=180-40
5x=140
x=140/5
=28
so
(3x-12)=3*28-12=72
52+2x=52+2*28=108
hope its help you.
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