Math, asked by Sirajbava, 1 year ago

The adjacent angles of a parallelogram are (3x-12) and (52+2x). Find the angles of the parallelogram?

Answers

Answered by HHK
10
Hi sum of adjacent angles of a parallelogram is 180.
Therefore (3x-12)+(52+2x) = 180
i.e. 5x+40 = 180
or 5x = 140
thus x = 28
Therefore the angles are
(3×28-12) and (52+2×28)
i.e. 72 and 108
Answered by yytctrading
6

Answer:

sum of adjacent angle of triangle=180degree.

(3x-12)+(52+2x)=180 degree

5x+40=180degree

5x=180-40

5x=140

x=140/5

=28

so

(3x-12)=3*28-12=72

52+2x=52+2*28=108

hope its help you.

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