Question

the adjacent figure shows the diagram of a picture frame having outer dimensions 28cm ×32cm and inner dimensions 20cm×24cm. if the the width of each section is the same , find the area of each section​

Answer 1

Answer:

hope it's helpful

plz mark as brillianest

Answer 2

Answer:  96cm square  other side 112cm square

Step-by-step :Width of section AEFB = width of the section CGHD

                                                                = 1/2 (32-24) cm = 4cm.

                       Width of section AEHD = width of the section BFGC

                                                                = 1/2 (28-20)cm = 4cm.

Clearly, each section of the frame is a trapezium.

                        Area of section AEFB = area of section CGHD

                                                              = 1/2 * (28+20) * 4 cm2 = 96cm2.

                       Area of section AEHD = area of section BFGC

                                                              = 1/2 * (32+24) * 4 cm2 = 112cm2. thank you hope it helps :)