Question

the adjacent figure shows the diagram of a picture frame having outer dimensions 28 cm into 30 cm and inner dimensions 20 cm and 24 cm if the width of each section in the same find the area of each section of the frame

Answer 1

height of 2 horizontal sections=32-24cm=8cm
height of 1 horizontal section=8/2=4cm
area of one horizontal section (trapezium)=(sum of parallel sides)/2×height
=(28+20)/2×4
=96cm^2
area of second horizontal section=area of first horizontal section
=96cm^2
height of 2 vertical sections = 28-20cm=8cm
height of 1 horizontal section=8/2=4cm
area of 1 vertical section=(sum of parallel sides)/2×height
=(24+32)/2×4
=112cm^2
area of second vertical section=are of first vertical section
=112cm^2