The adjacent plot shows variation of the terminal potential difference (V) of a cell as a function of current (I) drawn from it. Using the plot determine (1) the emf and (2) internal resistance of the cell
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Given, PD=v,current=I
Since V=E−ir⇒0.4=E−0.04r⇒E=0.4+0.20r...1
Similarly, E=0.8+0.12R....2
From equation 1 and 2 we get,
0.4+0.20r=0.8+0.12r⇒0.08r=0.4⇒r=40Ω
Now,
E=0.4+0.20×5=0.4+1=1.4volt
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