Question

the adjacent side of a rectangle are (2x-1) and (x+5) find its area?​

Answer 1

Answer:

area of rectangle =LXb

=(2x-1)(x+5)

2x(x+5)-1(x+5)

2x²+10x-x-5

2x²+9x-5=0

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• The area of the rectangle = 2x² + 9x - 5

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$\sf{\underline{\green{Given:-}}}$

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• The adjacent side of a rectangle are (2x - 1) and (x + 5).

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$\sf{\underline{\green{Find:-}}}$

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• The area of the rectangle = ?

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$\sf{\underline{\green{Explanation:-}}}$

$\sf{\underline\purple{Formula\:Used\:Here:-}}$

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$\bigstar\boxed{\sf{\red{Area\:of\: rectangle = Length \times Breadth}}}$

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$\sf{\underline{\pink{Putting\:the\:values:-}}}$

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$\longrightarrow \sf{ Area\: of\: rectangle = (2x - 1) \times (x + 5)}$

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$\longrightarrow \sf{ Area\: of\: rectangle = 2x^2 + 10x - x - 5}$

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$\longrightarrow{\gray{ \underbrace{\boxed{\underline{\underline{\blue{ \tt Area\: of\: rectangle = 2x^2 + 9x - 5 }}}}}}}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• The area of the rectangle = 2x² + 9x - 5

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$\rule{200}{2}$