The adjacent sides of a parallelogram ABCD measure 34 cm and 20 cm, and the diagonal AC measures 42 cm. Find the area of the parallelogram.
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ab=bc=34
dc=20
ac=42
using herons formula AREA of ΔACD
√s(s-a)(s-b)(s-c)
√48(48-34)(48-20)(48-42)
√48*14*28*6
=336
AREA of Δabc=336
∵are of parellepgram abcd =336*2=672
dc=20
ac=42
using herons formula AREA of ΔACD
√s(s-a)(s-b)(s-c)
√48(48-34)(48-20)(48-42)
√48*14*28*6
=336
AREA of Δabc=336
∵are of parellepgram abcd =336*2=672
Answered by
0
ab=bc=34
dc=20
ac=42
using herons formula AREA of ΔACD
√s(s-a)(s-b)(s-c)
√48(48-34)(48-20)(48-42)
√48*14*28*6
=336
AREA of Δabc=336
∵are of parellepgram abcd =336*2=672
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