Question

The adjacent sides of a parallelogram are 15cm and 8cm .if the distance brtween the longer sides is 4cm, find the distance between the shorter sides.

Answer 1

longer side=15cm
shorter side=8cm
height for shorter side=4cm

area of parellalogram
=base × height
=15cm×4cm
$60 {cm}^{2}$
area=base×height
60=8×height
$height = \frac{60}{8}$
= 7.5cm

Answer 2

The distance between the shorter sides is 7.5 cm.

Step-by-step explanation:

It is given that the adjacent sides of a parallelogram are 15cm and 8cm. The distance between the longer sides is 4cm.

Let the distance between the shorter sides is x cm.

Area of a parallelogram is

$Area=base\times height$

If base of the parallelogram is 15 cm then height is 4 cm.

$A_1=15\times 4=60$

If base of the parallelogram is 8 cm then height is x cm.

$A_2=8\times x=8x$

Equate the areas of parallelogram.

$8x=60$

Divide both sides by 8.

$x=\frac{60}{8}$

$x=7.5$

Therefore, the distance between the shorter sides is 7.5 cm.

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