Question

The adjacent sides of a parallelogram are 20 cm and 34 cm and one of its diagonal is 42 find the area of parallelogram

Answer 1

Let abcd is a parallelogram

ad=34

dc=20

and ac=42

in Δadc

s=34+20+42=48

area of adc=whole in under root(48*14*28*6)

area of adc=336 cm²

now, it is a parallelogram so,

ad=bc=34

dc=ab=20

ac common=42

so area of cba=336 cm²

adding adc and cba=336+336=672cm²

hene area of abcd=672cm²

4.6

34 votes

THANKS

97

Comments Report

zyan Expert

Ab=bc=34

dc=20 

ac=42

using herons formula  AREA of ΔACD 

√s(s-a)(s-b)(s-c)

√48(48-34)(48-20)(48-42)

√48*14*28*6

=336

AREA of Δabc=336

∵are of parellepgram abcd =336*2=67