The adjacent sides of a parallelogram are 3 cm and 7 cm. The ratio of its altitudes is
Answers
Answered by
3
Answer:
3:7 is the proper ratio.
you're welcome!
Answered by
7
Answer:
In parallelogram ABCD
AB = DC = 15 cm
BC = AD = 10 cm
Distance between longer sides AB and DC is 6 cm
Perpendicular DL = 6 cm
DM\bot⊥ BC
Area of Parallelogram= Base x Altitude
=AB x DL= 15 x 6 =90 cm^2
2
Let DM= x cm
∴ Area of || gm ABCD = BC x DM
\Rightarrow\ 90=10\ \times x⇒ 90=10 ×x
\Rightarrow x=\frac{90}{10}⇒x=
10
90
\Rightarrow\ x=9⇒ x=9cm
Attachments:
Similar questions