Math, asked by Gibin6216, 1 year ago

The adjacent sides of a parallelogram are 36 cm and 27 cm in length. if the distance between the shorter sides is 12 cm, then the distance between the longer sides is

Answers

Answered by Mankuthemonkey01
47
Your answer is \bold\boxed{9\:cm}

Here is how :-

Given, the distance between shorter sides i.e 27 is 12 cm. Let the distance between larger side be h cm.
(Distance between two sides is actually it's corresponding altitude)


If we assume 27cm as base, then height will be 12cm

We know that, area of a parallelogram = base × height.

Hence area = 27 × 12 = 324cm²


We also know that if we assume 36 cm as base and h cm as height then we will get

Area will remain the same because it's the same parallelogram.

Hence, 36 × h = 324

=> h = 324/36

h = 9cm

Hence the distance between larger side is
\boxed{9cm}

Hope it helps dear friend ☺️✌️
Answered by Anonymous
9

Step-by-step explanation:

Answer:

\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\linethickness{0.4mm}\put(8.6,3){\large\tt{A}}\put(7.7,0.9){\large\tt{B}}\put(9.5,0.7){\sf{\large{36 cm}}}\put(11.1,0.9){\large\tt{C}}\put(8,1){\line(1,0){3}}\qbezier(11,1)(11.5,2)(12,3)\put(9,3){\line(3,0){3}}\put(9.1,2){\sf{\large{12 cm}}}\put(9,1){\line(0,1){2}}\qbezier(8,1)(8.5,2)(9,3)\qbezier(11.5,2)(11.5,2)(9,3)\put(12.1,3){\large\tt{D}}\put(11.5,1.6){\sf{\large{27 cm}}}\put(11.65,2){\large\tt{M}}\put(8.9,0.7){\large\tt{N}}\end{picture}

Adjacent Sides of Parallelogram are 36 cm and 27 cm

Distance between Shorter Sides = 12 cm

Distance between Longer Sides = ?

\bigstar\:\boxed{\sf Area\:of\:Paralleogram=Base \times Height}

\underline{\bigstar\:\textsf{According to the given Question :}}

:\implies\sf Area\:of\:\parallel\: _{with \:base\:BC}=Area\:of\:\parallel\:_{with \:base\:CD}\\\\\\:\implies\sf Base \times Height = Base \times Height\\\\\\:\implies\sf BC \times AN=CD \times AM\\\\\\:\implies\sf 36 \times 12 =27 \times AM\\\\\\:\implies\sf \dfrac{36 \times 12}{27} = AM\\\\\\:\implies\sf 4 \times 4 = AM\\\\\\:\implies\underline{\boxed{\sf AM = 16\:cm}}

\therefore\:\underline{\textsf{Distance between longer sides is \textbf{16 cm}}}.

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