the adjacent sides of a parallelogram are 4cm and 12cm the distance between the longer sudes is 6cm the distancebetween the shorter sides is
Answers
Answered by
30
Area of a parallelogram = base × height
ATQ;
Let the distance between the shorter sides be d. Then;
12×6=4×d
d=72/4
d=18
Hence; the distance between the shorter sides is 18cm...
ATQ;
Let the distance between the shorter sides be d. Then;
12×6=4×d
d=72/4
d=18
Hence; the distance between the shorter sides is 18cm...
Answered by
23
Dear Student,
● Answer -
y = 18 cm
● Explanation -
Suppose,
length of longer side = l = 12 cm
length of shorter side = b = 4 cm
distance between longer sides = x = 6 cm
distance between shorter sides = y = ?
Area of parallelogram is given by -
l × x = b × y
12 × 6 = 4 × y
72 = 4y
y = 72 / 4
y = 18 cm
Hence, distance between shorter sides is 18 cm.
Thanks dear. Hope this helps you...
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