Math, asked by alibabafayez, 4 months ago

the adjacent sides of a parallelogram measure 5.4 cm and 3.6 cm respectively.if the area of the parallelogram is 21.6 cm2. find the length of the altitude on each these adjacent site​

Answers

Answered by prabhas24480
4

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 \large \tt  \red{✦Answer✦}

Since 8*6 = 48 => one of the sides is the height as area parallelogram = Base * Height! This indicates the shape is really a rectangle. But let us see if this can be proved.

Consider any one diagonal which bisects the parallelogram into 2 equal halves.

The area of the triangle with the two adjacent sides and the diagonal

= 48/2 = 24 sq. cm

Area of this triangle = 1/2 absinC = 24

1/2 * 6 * 8 * SINC = 24

24 * SIN C = 24

SIN C = 1

C = 90 Degrees

This indicates that the said parallelogram is a rectangle and both diagonals are the same length

Diagonal length = sqrt(6² + 8²) = sqrt(36 + 64) = sqrt (100) = 10cm

Both Diagonals are 10cm long

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Answered by UniqueBabe
5

Answer:

Since 8*6 = 48 => one of the sides is the height as area parallelogram = Base * Height! This indicates the shape is really a rectangle. But let us see if this can be proved.

Consider any one diagonal which bisects the parallelogram into 2 equal halves.

The area of the triangle with the two adjacent sides and the diagonal

= 48/2 = 24 sq. cm

Area of this triangle = 1/2 absinC = 24

1/2 * 6 * 8 * SINC = 24

24 * SIN C = 24

SIN C = 1

C = 90 Degrees

This indicates that the said parallelogram is a rectangle and both diagonals are the same length

Diagonal length = sqrt(6² + 8²) = sqrt(36 + 64) = sqrt (100) = 10cm

Both Diagonals are 10cm long

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