Question

the adjacent sides of a rectangle are (2x-1) and (x-5 ) . find its area​

Answer 1

Answer:Area of rectangle= length × breadth = (2x-1) × ( x-5)

=2x(x-5) -1(x-5)

=2x^2 - 10x -x +5

=2x^2 - 11x +5

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Answer 2

Given:

• The adjacent sides of a rectangle are (2x-1) and (x-5 ).

To find:

• Its area ?

Solution:

• Let's consider ABCD is a rectangle.

Where,

• Adjacent sides:

1. (2x - 1)
2. (x - 5)

• Let breadth of the rectangle be b

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Finding Area of the rectangle,

→ Area = L × B

→ (2x - 1)(x - 5)

→ 2x² - 10x - 1x + 5

→ 2x² - 9x + 5

∴ Hence, Area of the rectangle is 2x² - 9x + 5

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Let's verify this,

→ L × B = Area

→ (2x - 1)(x - 5) = 2x² - 9x + 5

→ 2x² - 10x - 1x + 5 = 2x² - 9x + 5

→ 2x² - 9x + 5 = 2x² - 9x + 5

LHS = RHS

• Hence Verified.