the adjacent sides of a rectangle are -6p³+7p²q²+pq and 7pq -5p³+9p²q². find its perimeter
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Answered by
32
Answer:
formulae for perimeter of rectangle is 2(l+b)
so
2[(-6p^3+7p^2q^2+pq)+(7pq-5p^3+9p^2q^2)]
=2[-6p^3-5p^3+7p^2q^2+9p^2q^2+pq+7pq]
=2[16p^2q^2+8pq-11p^3]
=32p^2q^2+16pq-22p^3
the perimeter is this much
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