Question

the adjacent sides of parallelogram are 4a, 3a. the angle b/w them is 60, then one of the diagonal of the parallelogram? ​

Answer 1

Answer:

Required Answer:-

Two adjacent sides and the respective diagonal makes a triangle and here, we have the length of two sides and the angle between them..

By using cosine law,

(Refer to the attachment)

➙ d² = (4a)² + (3a)² - 2×4a×3a×cos 60°

➙ d² = 16a² + 9a² - 24a² × 1/2

➙ d² = 25a² - 12a²

➙ d² = 13a²

➙ d = √(13a²)

➙ d = a√13

➙ d ≈ 3.61 a (Ans)

One of the diagonal will have length 3.61a. Similarly you can find the length of other diagonal with the included angle as 120°.

$\underline\mathbb\pink{hope~it~will~help~you :}$

Answer 2

Answer:

∠A=60°

In parallelogram Opposite angles are equal .

So ∠C=60°

In parallelogram adjacent sides sum up to give 180°

So ∠A+∠D=180°

∠D=180−60=120°

So ∠A+∠B=180°

∠B=180−60=120°

Explanation:

what a decision from your side I can't even stop my laugh hahahaha don't be hurted