the adjacent sides of parallelogram are 4a, 3a. the angle b/w them is 60, then one of the diagonal of the parallelogram?
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Step-by-step explanation:
the adjacent sides of parallelogram are 4a, 3a. the angle b/w them is 60, then one of the diagonal of the parallelogram?
Required Answer:-
Two adjacent sides and the respective diagonal makes a triangle and here, we have the length of two sides and the angle between them..
By using cosine law,
(Refer to the attachment)
➙ d² = (4a)² + (3a)² - 2×4a×3a×cos 60°
➙ d² = 16a² + 9a² - 24a² × 1/2
➙ d² = 25a² - 12a²
➙ d² = 13a²
➙ d = √(13a²)
➙ d = a√13
➙ d ≈ 3.61 a (Ans)
One of the diagonal will have length 3.61a. Similarly you can find the length of other diagonal with the included angle as 120°.
I hope it will help you ✌️☺️
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