Math, asked by ojasbansode, 8 months ago

The adjacent sides of rectangle are (4x + 5y) and (4x – 5y). Find the area ?​

Answers

Answered by THRISHALDOMA
0

Answer:

(a+b)(a-b) = a^2 - b^2

Step-by-step explanation:

(4x + 5y)(4x - 5y) = (4x)^2 - (5y)^2

16x^2 - 25y^2

Answered by SteffiPaul
0

Therefore the area of the rectangle is ( 16x² - 25y² ) units².

Given:

The Length of the rectangle = L = ( 4x + 5y ) units

The breadth of the rectangle = B = ( 4x - 5y ) units

To Find:

The area of the rectangle.

Solution:

The given question can be solved as shown below.

Given that,

The Length of the rectangle = L = ( 4x + 5y ) units

The breadth of the rectangle = B = ( 4x - 5y ) units

The area of the rectangle = A = length × breadth

⇒ The area of the rectangle = ( 4x + 5y ) × ( 4x - 5y )

               [ ∵ ( a + b ) ( a - b ) = a² - b² ]

⇒ The area of the rectangle = (4x)² - (5y)²

⇒ The area of the rectangle = 16x² - 25y²

Therefore the area of the rectangle is ( 16x² - 25y² ) units².

#SPJ2

Similar questions