The adjecent angles of a parallelogram are (5x-3)° and (5x-67)°. Find all the angles of the parallelogram
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Solution :
Given, Adjacent angles of a parallelogram (5x - 3)° , ( 5x - 67)° .
We know that
Sum of Adjacent angles of a parallelogram are 180° or supplementary.
⇒ 5x - 3 + 5x - 67 = 180
⇒ 10x - 70 = 180
⇒ 10x = 250
⇒ x = 25°
Therefore,
Angles of a parallelogram are
5x - 3 = 5 ( 25 ) - 3 = 125 - 3 = 122
5x - 67 = 5 ( 25) - 67 = 58
So, 122 , 58 , 122 , 58 are the angles of the parallelogram.
Given, Adjacent angles of a parallelogram (5x - 3)° , ( 5x - 67)° .
We know that
Sum of Adjacent angles of a parallelogram are 180° or supplementary.
⇒ 5x - 3 + 5x - 67 = 180
⇒ 10x - 70 = 180
⇒ 10x = 250
⇒ x = 25°
Therefore,
Angles of a parallelogram are
5x - 3 = 5 ( 25 ) - 3 = 125 - 3 = 122
5x - 67 = 5 ( 25) - 67 = 58
So, 122 , 58 , 122 , 58 are the angles of the parallelogram.
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