Question

The adjoining cylindrical vessel is 70 CM high and the radius
of its base is 35cm. If it contains some water up to the heightof 20 cm, how much water is required to fill the vessel completely​.​

Answer 1

Answer:

Answer:

$\large\boxed{\pink{\sf \leadsto The \ Volume \ of \ water \ needed \ to \ be \ filled \ is \ 192,500 cm^3}}$

Step-by-step explanation:

Given that ,

• cylindrical vessel is 70 cm high and the radius of its base is 35cm .
• it contains some water up to the height of 20 cm .
• And we need to find the water required to fill it completely .

Let us take the Volume of Cylinder be V and the volume of cylinder filled be v .

Let the volume required to be filled be X .

$\begin{gathered}\tt:\implies v + x = V \:\: \bigg\lgroup \red{\bf As \ per \ our \ assumption }\bigg\rgroup \\\\\tt:\implies x = V - v \\\\\tt:\implies x = \pi r^2 H - \pi r^2 h \\\\\tt:\implies x = \pi r^2 ( H - h ) \\\\\tt:\implies x = \pi r^2 ( 70 cm - 20 cm ) \\\\\tt:\implies x = \dfrac{22}{7} \times (35 cm)^2 \times 50 cm \\\\\tt:\implies x = \dfrac{22\times 35 cm \times 35 cm }{7} \times 50 cm \\\\\underline{\boxed{\red{\tt \longmapsto Volume_{fill } = 192,500 cm^3}}}\end{gathered}$

Hence the required volume of water to be filled is 192,500cm³ .

Answer 2

Step-by-step explanation:

Answer:

Answer:

$\large\boxed{\pink{\sf \leadsto The \ Volume \ of \ water \ needed \ to \ be \ filled \ is \ 192,500 cm^3}}$

Step-by-step explanation:

Given that ,

cylindrical vessel is 70 cm high and the radius of its base is 35cm .

it contains some water up to the height of 20 cm .

And we need to find the water required to fill it completely .

Let us take the Volume of Cylinder be V and the volume of cylinder filled be v .

Let the volume required to be filled be X .

$\begin{gathered}\tt:\implies v + x = V \:\: \bigg\lgroup \red{\bf As \ per \ our \ assumption }\bigg\rgroup \\\\\tt:\implies x = V - v \\\\\tt:\implies x = \pi r^2 H - \pi r^2 h \\\\\tt:\implies x = \pi r^2 ( H - h ) \\\\\tt:\implies x = \pi r^2 ( 70 cm - 20 cm ) \\\\\tt:\implies x = \dfrac{22}{7} \times (35 cm)^2 \times 50 cm \\\\\tt:\implies x = \dfrac{22\times 35 cm \times 35 cm }{7} \times 50 cm \\\\\underline{\boxed{\red{\tt \longmapsto Volume_{fill } = 192,500 cm^3}}}\end{gathered}$

Hence the required volume of water to be filled is 192,500cm³ .