Question

the adjoining figur shows a metal pipe 77cm long the inner diameter of cross section is 4cm and the outer one is 4.4 cm find its inner curved surface area and outer curved surface area and total curved surface area

Answer 1

inner CSA =968cm2 and outer=1064.2cm2

Answer 2

Step-by-step explanation:

Given h = 77cm.

Given Inner Diameter of the cross-section d = 4cm.

Then the radius r = 4/2

                              = 2cm.

Given that Outer Diameter of the cross-section d = 4.4cm.

Then the radius R = 4.4/2

                               = 2.2cm.

(1)  Inner curved surface area:

= 2pirh

= 2 * 22/7 * 2 * 77

= 2 * 22 * 11/7

= 968cm^2.

(2) Outer curved surface area:

= 2piRh

= 2 * 22/7 * 2.2 * 77

= 1064.8cm^2

(3) Total surface area:

= 2pirh + 2piRh + 2pi(R^2 - r^2)

= 968 + 1064.8 + 2 * 22/7((2.2)^2 - (2)^2)

= 968 + 1064.8 + 2 * 22/7(4.84 - 4)

= 2032.8 + 2 * 22/7(0.84)

= 2032.8 + 2 * 22 * 0.12

= 2032.8 + 5.28

= 2038.08cm^2.

Hope this helps!