the adjoining figure ΔQPR = 62° and ΔPRQ = 64°. If OQ and OR and bisectors of
∟PQR and ∟PRQ respectively, then ∟OQR and ∟QOR :
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Answered by
2
Answer:
b . 27 , 121
is the right answer
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hope it helps
Answered by
6
Answer:
QPR=80°
∠PQR+∠QPR+∠QRP=180°
∠PQR+∠QRP=100°
2(x+y)=100°
x+y=50°
So, in △QOR
x+y+∠QOR=180°
∴∠QOR=180°−50°
=130°
Step-by-step explanation:
l hope it will help u ☺️☺️
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