Question

The adjoining figure shows a circle with centre O in which a diameter AB bisects the chord PQ at point R. If PR=RQ=8 cm and RB=4 cm, find the radius of the circle.​

Answer 1

hi dear

your answer is

AB bisects chord PQ at point C.

Therefore,

PR=QR=8cm

RB=4cm

Let, radius OA=OB=r

  OB=OR+RB

=>r=OR+4

=>OR=r−4  (i)

Now,

  OP2=OR2+PR2

=>r2=(r−4)2+82 (using (i)

=>r2=r2−8r+16+64

=>8r=80

=>r=10cm

The radius of the circle is 10cm

hopes its helps you

have a great day

Answer 2

Answer:

AB bisects chord PQ at point C.

Therefore,

PR=QR=8cm

RB=4cm

Let, radius OA=OB=r

 OB=OR+RB

=>r=OR+4

=>OR=r−4  (i)

Now,

 OP2=OR2+PR2

=>r2=(r−4)2+82 (using (i)

=>r2=r2−8r+16+64

=>8r=80

=>r=10cm

The radius of the circle is 10cm

hopes its helps you

have a great day

Step-by-step explanation:

hope u understand it pls mark me brainliest :D