The adjoining figure shows a circle with centre O in which a diameter AB bisects the chord PQ at point R. If PR=RQ=8 cm and RB=4 cm, find the radius of the circle.
Answers
Answered by
7
hi dear
your answer is
AB bisects chord PQ at point C.
Therefore,
PR=QR=8cm
RB=4cm
Let, radius OA=OB=r
OB=OR+RB
=>r=OR+4
=>OR=r−4 (i)
Now,
OP2=OR2+PR2
=>r2=(r−4)2+82 (using (i)
=>r2=r2−8r+16+64
=>8r=80
=>r=10cm
The radius of the circle is 10cm
hopes its helps you
have a great day
Answered by
1
Answer:
AB bisects chord PQ at point C.
Therefore,
PR=QR=8cm
RB=4cm
Let, radius OA=OB=r
OB=OR+RB
=>r=OR+4
=>OR=r−4 (i)
Now,
OP2=OR2+PR2
=>r2=(r−4)2+82 (using (i)
=>r2=r2−8r+16+64
=>8r=80
=>r=10cm
The radius of the circle is 10cm
hopes its helps you
have a great day
Step-by-step explanation:
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