Question

the adjoining figure shows a metal pipe 77 cm long.The inner diameter of cross section is 4 cn and the oiter one is 4.4 cm.find it (i)inner curved surface area (ii) outer curved surface area (iii) total surface area.

Answer 1

Heya...
here is the solution..
Given..
height=77cm
inner radius=4/2=2cm
outer radius=4.4/2=2.2cm
To find..
I) inner curved surface area..
C.S.A = 2πrh
2×22/7×2×77
968cm²
ii)outer curved surface area..
C.S.A = 2πrh
2×22/7×22/10×77
1064.8cm²
iii) total surface area...
2πrh+2πRh+2π(r²-R²)
968+1064.8+2×22/7(2²-2.2²)
2032.8+2×22/7×2/10×42/10
2032.8+5.28
2038.08cm²...

plz marks as brainliest.. :)

Answer 2

Answer:

Step-by-step explanation:

Given..

height=77cm

inner radius=4/2=2cm

outer radius=4.4/2=2.2cm

To find..

I) inner curved surface area..

C.S.A = 2πrh

2×22/7×2×77

968cm²

ii)outer curved surface area..

C.S.A = 2πrh

2×22/7×22/10×77

1064.8cm²

iii) total surface area...

2πrh+2πRh+2π(r²-R²)

968+1064.8+2×22/7(2²-2.2²)

2032.8+2×22/7×2/10×42/10

2032.8+5.28

2038.08cm²...

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