Question

the adjoining figure shows an equilateral triangle oab with each side=2a units find the coordination of the vertices​

Answer 1

Answer:

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Answer 2

given : side = 2a

To find : coordination of the vertices​

solution :

construction : lets draw AC ⊥ OB

since , OB = 2a

OC =

$\frac{1}{2}OB \\\\ \frac{1}{2}\times 2a\\\\= a$

i.e OC = a

now , in triangle AOC

Using the pythagoras theorem

OA²= AC²+OC²

(2a)² = AC² + (a)²

4a² = AC² + (a)²

4a² - a² = AC²

3a² = AC²

AC = √3a

thus , The coordinates are

coordinate of O = (0,0)

coordinate of B = (2a,0)

coordinate of C = (a, √3a)

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