Question

The adjoining figure shows an equilateral triangle OAB with each side = 2a units. Find the coordinates of the vertices.
Can anyone explain the sum with the solution .
plz​

Answer 1

Answer:

O(0,0), B(2a,0), (a, √3 *a)

Step-by-step explanation:

O is the origin so co-ordinates will be (0,0)

and B is at a distance of 2a from y co-ordinate and it's on x -axis so the co-ordinates of B (2a, 0)

so now from vertices A draw a line perpendicularly to x axis

it will divide the line OB into two equal parts since it is a altitude from vertices A

the altitude = median for an equilateral triangle

so the distance from y axis will be a,

so the x co-ordinates is a

let's take the intersection point C

then AC will be altitude

so value of AC = √(2a^2-(a) ^2)

so AC= √3 a

so vertices A = (a, √3a)