Math, asked by rajeshmutha007, 8 days ago

The adjoining figure shows the location of four flower beds in a park. If the outer dimensions of the park are 34 m x 28 m and the inner dimensions are 24 m x 18 m, find the area of each flower bed. All flower beds have the same width. ​

Answers

Answered by Itzintellectual
3

Answer:

520m^2

Step-by-step explanation:

34\times28-24\times18=520m^2

Answered by Surshti123
0

Answer:

The area of shorter flower bed is 31.6 m^2 and the area of longer flower bed is 38.8 m^2.

One direction constrains the width of the flower beds to be = 28 - 18 / 2 = 5

The other direction constrains the width to be = 34 - 24 / 2 = 5

Two flower beds each have bases 28 and 18, with height of 5;

and two flower beds each have bases 34 and 24 with height of 5.

Calculate each flower bed area.

For each of the shorter flower beds = 28 + 18 / 5 = 31.6 m^2

For each of the longer flower beds areas = 34 + 24 / 5 = 38.8 m^2

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