Question

The adjoining figure shows two straight lines AB and
CD intersecting at point P. If ZBPC = 4x - 5º and
ZAPD = 3x + 15°, find :
1 the value of x
2 angle APD​

Answer 1

Answer:

Step-by-step explanation:

X = 20 ∠BPC = ∠APD =75° &  ∠BPD = 105°

Step-by-step explanation:

∠BPC = ∠APD  ( opposite angle)

4X - 5 = 3X + 15

=> X = 20

∠BPC = ∠APD = 4 * 20 - 5  = 75°

∠BPC = ∠APD =75°

∠BPD = 180° - ∠APD  = 180° - 75° = 105°

∠BPD = 105°

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Answer 2

Answer:

and

CD intersecting at point P. If ZBPC = 4x - 5º and

ZAPD = 3x + 15°, find :

1 the value of x

2 angle APD