Physics, asked by cmkumariyogesh, 8 months ago

The adjoining Speed- time graph shows motion of a car. Find the following

i. Speed of the car at 11 second?

ii. During which part of the car’s journey (a, b, c or d) is the car having a

negative acceleration?

iii. During which part of the car’s journey (a, b, c or d) is the car having

maximum rate of change of velocity?

iv. Distance covered by the car during the journey 4 to 8 seconds?

Answers

Answered by aryansharma91
0

Since velocity is not changing, acceleration is equal to zero.

(b) Reading the graph, velocity=20ms

−1

(c) s = area of the figure enclosed under v-t graph. Distance covered in 15s, s=ut=20×15=300m

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