Question

The age (in years) of 12 persons are given below.

42, 48, 48, 50, 56, 43, 47, 56, 60, 65, 56, 65.

Find the mean, median and mode of their ages. Also find range of the given data.​

Answer 1

Given:

The age of 12 people is as follows:

42, 48, 48, 50, 56, 43, 47, 56, 60, 65, 56, 65.

To find:

The mean, mode and median of their ages.

Solution:

Mean of their ages= Sum of ages/ Total number of people

$\frac{42 + 48 + 48 + 50 + 56 + 43 + 47 + 56 + 60 + 65 + 56 + 65}{12}$

$= \frac{636}{12}$

= 53

Mode is the most frequently occurring value. In the given data 56 is occurring most frequently, therefore the mode of the given data is 56.

Median is the middle number of the data when it is arranged in ascending or descending order.

Arranging the data in ascending order we get:

42, 43, 47, 48, 48, 50, 56, 56, 56, 60, 65, 65

The middle numbers are 50 and 56.

Therefore median = (50+56) /2

Median = 53

The range of the difference between the maximum and minimum values that are mentioned in the data= 65-42 = 23

The mean, mode and median of the given data are 53, 56 , 53 respectively.

The range of the data is 23.

Answer 2

Given : The age (in years) of 12 persons are given below.

42, 48, 48, 50, 56, 43, 47, 56, 60, 65, 56, 65.

To Find :  mean, median and mode of their ages. Range of the given data.​

Solution:

42, 48, 48, 50, 56, 43, 47, 56, 60, 65, 56, 65.

Mean = (42+48+48+50+56+43+47+56+60+65+ 56+65 )/12

= 636/12

= 53

42, 48, 48, 50, 56, 43, 47, 56, 60, 65, 56, 65.

arrange in order

42, 43,  47, 48, 48, 50, 56, 56,  56, 60, 65, 65

Range = 65 - 42  = 23

Median =  (50 + 56)/2 = 53

Mode = 56  ( maximum 3 times )

MEAN = 53

MEDIAN = 53

MODE = 56

RANGE = 23

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