Math, asked by anushajain8874, 11 months ago

The Age Of A And B Are In The Ratio 7:8.Ten Years Ago Their Ages Will Be In The Ratio 5:6
Find Their Present Ages

Answers

Answered by sunnysinghdollysingh
1

Answer:

35:40

Step-by-step explanation:

LET AGES BE 7X:8X

TEN YEARS AGO RATIO IS 5:6

SO ,

7X-10/8X-10=5/6

2X=10

X=5

SUBS IN 7X:8X

WHICH GIVES 35:40

MARK AS BRAINLIEST IF U LIKE SOLUTION

Answered by ram5556
1

Answer:

The present age of A = 7x

The present age of B = 8x

After Ten Years .

The age of A = 7x + 6

The age of B = 8x + 6

7x + 6 = 5

8x + 6 = 6

6(7x + 6) = 5( 8x + 6)

42x + 36 = 40x +30

42x - 40x = 36 - 30

2x = 6

X= 6

2

X= 3 .

The present age of A = 7x

7×6 = 42 years

The present age of B = 8x

8×6= 48 years

Thanks .

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