Math, asked by susi42, 1 year ago

the age of A and B in the ratio 3:8 six years hence their ages will be in the ratio 4:9 .The present age of A is ?​

Answers

Answered by Anonymous
23

• Let present age of A be 3M and present age of B be 8M

6 years later

  • Age of A = 3M + 6

  • Age of B = 8M + 6

» Six years hence their ages (age of A and b) will be in the ratio 4:9.

According to question;

\dfrac{3M\:+\:6}{8M\:+\:6}\:=\:\dfrac{4}{9}

Cross-multiply them

→ 9(3M + 6) = 4(8M + 6)

→ 27M + 54 = 32M + 24

→ 27M - 32M = 24 - 54

→ - 5M = - 30

→ 5M = 30

M = 6

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From above calculations we have M = 6

Now we have to find the present age of A and B

Present age of A = 3M

→ 3(6)

→ 18 years

Present age of B = 8M

→ 8(6)

→ 48 years

But according to question we have to find the present age of A.

So,

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Present age of A = 18 years

_________ [ ANSWER ]

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✡ VERIFICATION :

We have M = 6 (from above calculations)

Put value of M in this equation :

\dfrac{3M\:+\:6}{8M\:+\:6}\:=\:\dfrac{4}{9}

=> \dfrac{3(6)\:+\:6}{8(6)\:+\:6}\:=\:\dfrac{4}{9}

=> \dfrac{18\:+\:6}{48\:+\:6}\:=\:\dfrac{4}{9}

=> \dfrac{24}{54}\:=\:\dfrac{4}{9}

=> \dfrac{4}{9}\:=\:\dfrac{4}{9}

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Answered by agampreetsehgal2008
0

Answer:

the age of A and B in the ratio 3:8 six years hence their ages will be in the ratio 4:9 .The present age of A is ?​

Step-by-step explanation:

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