Question

the age of A and B is in the ratio of 8:3 .six years after thier agewill be in ratio of 9:4 .find the present age?​

Answer 1

Answer:

So ,present age of A is 18 years.

Step-by-step explanation:

Let the present age of A and B be x and y respectively.

Ratio of present age of A and B will be,

x/y=3/8. eq(1)

Ratio of age after six year latter will be

x+6/y+6=4/9. eq(2)

Now,solve eq(1) and(2) ,we get

Hence,value of x is 18.

So ,present age of A is 18 years.

Answer 2

Answer:

$\huge\bold\red{Given:}$

• the age of A and B is in the ratio of 8:3 .six years after thier agewill be in ratio of 9:4

$\huge\bold\red{To \: Find:}$

• find the present age?

$\huge\bold\red{Solution:}$

Suppose that the present ages of A and B are 8x yrs and 3x yrs.Then, (8x + 6) : (3x + 6) = 9 : 4

$\bf32x + 24 = 27x + 54 \\ \bf \: ⇒ 5x = 30 \\ \bf⇒ x = 6</strong></p><p><strong>[tex] \bf32x + 24 = 27x + 54 \\ \bf \: ⇒ 5x = 30 \\ \bf⇒ x = 6$

$\bf \: Now, \: present \: age of \: A = 8  \times 6 yrs = 48 yrs \\ </strong></p><p></p><p><strong>[tex] \bf \: Now, \: present \: age of \: A = 8  \times 6 yrs = 48 yrs \\ \bf \: Present \: age \: of  \: B = 3  \times  6 yrs = 18 yrs$

$\sf\pink{= > present \: age \: of \: A =48 \: years }\\ \sf\blue{= > present \: \: age \: \: of \:  B =18 \: years}$