Question

the age of a boy is one third of his father. if sum of their ages is 80 years. find the age of each of them? answer: 60,20 but how it came????​

Answer 1

Answer:

20,60

Step-by-step explanation:

let the age of the boy's father be X

Then,the boy's age=1/3of X

According to question,

x+1/3x=80

3x+x/3=80

4x =80×3

x =240/4

=60

So, the father's age=x=60years

And,the boy's age=1/3 of X

=1/3×60

=20years

Answer 2

answer :-

let the age of father = x

let the age of son = 1/3 × X

father's age + son age = 80

$\frac{1}{3} \times x + x = 80$

$\frac{x}{3} + \frac{x}{1} = 80$

$\frac{x + 3x}{3} = 80$

$\frac{4x}{3} = 80$

$4x = 80 \times 3$

$4x = 240$

$x = \frac{240}{4}$

$x = 60$

father's age = X = 60

so, father's age is 60 years

son's age is one third age of father =

$\frac{1}{3} \times x$

$\frac{1}{3} \times 60 = 20$

so, son's age is 20 years

full explanation, correct answer and all steps are right

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