Math, asked by shravanrajani13, 1 year ago

the age of a father 10 yeara ago was thrice the age of his son. ten years hence,father's age will be twice of his son. the ratio of their present ages is_______.


A 5 : 2
B 7 : 3
C 9 : 2
D 13 : 4

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Answers

Answered by Anvesh06
2
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20.
∴ Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Hence, the correct answer is Option "B".
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