the age of a father is 2 years more than five times the age of his son. If the sum of their ages is 38 years, find the age of each of them
Murarji:
Son = X , Father = 5X + 2 , Now Son + Father = 38 i.e. X + 5X + 2 =38 so X = 6 Therefore Son's age is 6 and Father ' s age is 32
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Answered by
6
Let the age of son be a
Father's age = 5a+ 2
Sum of their ages = 38
=> a+ 5a + 2 = 38
=> 6a = 36
=> a = 6
Son's age = 6 years
Father's age = 32 years
Father's age = 5a+ 2
Sum of their ages = 38
=> a+ 5a + 2 = 38
=> 6a = 36
=> a = 6
Son's age = 6 years
Father's age = 32 years
Answered by
0
let the father age be 2x+2, son's age x
2x+2+x=38
3x+2=38
3x=38-2=36
x=36/3=12
12 is the answer
2x+2+x=38
3x+2=38
3x=38-2=36
x=36/3=12
12 is the answer
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