Math, asked by mcgamer, 1 month ago

The age of a father is 3 times the age of his son. 5 years ago father was five
times as old as his son was . Find their present age.

Answers

Answered by kumarsurjeet2811535
0

Answer:

The age of a father is 3 times the age of his son. 5 years ago father was five

times as old as his son was . Find their present age.

The age of a father is 3 times the age of his son. 5 years ago father was five

times as old as his son was . Find their present age.

Answered by ritikarai121105
1

Answer:

Let the age of the boy be x. Then his father age is 3x.

Step-by-step explanation:

After 5 years their ages

Father=3x - 5

Son = x - 5

3x - 5 = 5(x - 5)

3x - 5 = 5x - 25

-5 + 25 = 5x - 3x

20 = 2x

10 = x

Therefore son age is 10 years and his father age is 30 years. (3x, x = 10 then 3×10=30)

Hope it helps you

:-)))

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