The age of a father is 4 time as old as his daughter if the sum of the of their ages is 60 years find their present ages.
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Step-by-step explanation:
Let the father’s age now be F and that of the son S. Let us frame the relations:
F = 4S … (1)
F-10 = 10(S-10) … (2).
Put the value of F from (1) into (2) to get
4S - 10 = 10(S-10), or
4S - 10 = 10S - 100, or
6S = 90, or
S = 15 and F = 60.
Check: Ten years ago the Father was 50 years and the Son 5 years. The ratio of the Father’s age to the Son’s age then was 10.
The Father is 60 years now
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