Question

the age of a father is 5 years more than the age of six times of his son's age. after 7 years the age of father will be 3times than his son's age. find their present age?

Answer 1

let the sons age be x
son = x+7 = 1
father = 6x+5+7= 3
3x+21=6x+12
3x+21=6x+12
-3x=-9
x=3 son = 3 years
father = 23 years

Answer 2

present age of son=x
present age of father will be 6x+5

AFTER 7 YEARS
age of son=x+7
age of father=3x+7

The answer will come in algebraic form not numerical form.
Therefore the answer is
son x+7
father 3x+7