the age of a father is 5 years more than the age of six times of his son's age. after 7 years the age of father will be 3times than his son's age. find their present age?
Answers
Answered by
2
let the sons age be x
son = x+7 = 1
father = 6x+5+7= 3
3x+21=6x+12
3x+21=6x+12
-3x=-9
x=3 son = 3 years
father = 23 years
son = x+7 = 1
father = 6x+5+7= 3
3x+21=6x+12
3x+21=6x+12
-3x=-9
x=3 son = 3 years
father = 23 years
ravigodara:
well tried bro but totally wrong
sorry
Answered by
2
present age of son=x
present age of father will be 6x+5
AFTER 7 YEARS
age of son=x+7
age of father=3x+7
The answer will come in algebraic form not numerical form.
Therefore the answer is
son x+7
father 3x+7
present age of father will be 6x+5
AFTER 7 YEARS
age of son=x+7
age of father=3x+7
The answer will come in algebraic form not numerical form.
Therefore the answer is
son x+7
father 3x+7
totally wrong
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