Question

the age of a father is 7 times than the age of his son. After 4 years the sum of their age will be 56 years. find the present age of his son​

Answer 1

Answer:

The present age the son is 6 years.

Step-by-step explanation:

Let the present age of father and son be x and y respectively .

According to the question.

Father's age =7 X son's age

i. e., x=7y ------->( i)

After 4 years.

x+4+y+4=56

x+y+8=56

x+y=56-8

x+y=48

7y+y =48 [ by eq. i ]

8y=48

Y=6

.: Present age of the son is 6years.

(i) -----> x=7y

x=7(6)

x=42

.: present age of father is 42years.